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4x^2+1.52x-0.76=0
a = 4; b = 1.52; c = -0.76;
Δ = b2-4ac
Δ = 1.522-4·4·(-0.76)
Δ = 14.4704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.52)-\sqrt{14.4704}}{2*4}=\frac{-1.52-\sqrt{14.4704}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.52)+\sqrt{14.4704}}{2*4}=\frac{-1.52+\sqrt{14.4704}}{8} $
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